Estimate the radiation pressure of your finger tip

AI Thread Summary
To estimate the radiation pressure from a 100-W bulb at a distance of 5.0 cm, the intensity is calculated using the formula I = Power/(4*pi*d^2), yielding an intensity of approximately 1.27 x 10^5 W/m^2. The pressure is then derived by dividing this intensity by the speed of light, resulting in a pressure of about 4.23 x 10^-5 pascals. The force on a fingertip with an area of 1.5 cm² is calculated by multiplying the pressure by the area, leading to a force of approximately 6.35 x 10^-7 N. Discussions emphasize the importance of considering photon momentum and the average wavelength of the light emitted by the bulb. The calculations highlight the need for careful unit management throughout the process.
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Homework Statement



Estimate the radiation pressure due to a 100-W bulb at a distance of 5.0 cm from the center of the bulb. Assume that light is complitely absorbed.

Estimate the force exerted on your fingertip if you place it at this point. Assume area of the fingertip to be 1.5 cm2.

Homework Equations



P = I/c
I = Power/(4*pi*d2)??

The Attempt at a Solution


I don't know how to solve for intensity. I think it should have units of W/m^2 so I would guess it would be 100/(4*pi*.05*.05) = Power/(4*pi*d2), since 4*pi*d*d would be the area of a sphere of radius d but I doubt it is correct.

For the second part it would just be the pressure I get in the first part times 0.00015 (1.5 cm2 in m2) for force.

Thanks in advance!
 
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Yes, you need the surface area of a sphere radius=5cm.
Then you have the power/area at that distance ( since all the power from the bulb reaches the surface of this sphere)
Now you need to know how many photons/sec from the bulb and how much momentum/photon.

It's probably easier to do this in stages rather than just write a single equation - be carefull of the units.
 
mgb_phys said:
Yes, you need the surface area of a sphere radius=5cm.
Then you have the power/area at that distance ( since all the power from the bulb reaches the surface of this sphere)
Now you need to know how many photons/sec from the bulb and how much momentum/photon.

It's probably easier to do this in stages rather than just write a single equation - be carefull of the units.

So am I correct in saying that pressure is intensity over the speed of light? If so, am I also correct in my formula for intensity?

I'm not quite sure how I work in momentum/second (momentum/photon and photons/second).
 
The momentum of a photon is h / wavelength - where h is Planks constant.
The energy of a photon is h * frequency or h * speed of light / wavelength.

You will have to estimate an average wavelength for the light bulb (hint the filament is around 2-3000K + Wein's law)
 
mgb_phys said:
The momentum of a photon is h / wavelength - where h is Planks constant.
The energy of a photon is h * frequency or h * speed of light / wavelength.

You will have to estimate an average wavelength for the light bulb (hint the filament is around 2-3000K + Wein's law)

How is this not giving me more than I need? The title's radiation is just about light not radiation per se.

My units work out if I have (100 W/(4*pi*.05*.05 m2)/c = 1.something*10-5 pascals which are the units I want for the question (thank you masteringphysics)
 
100/(4*pi*.05*.05) is the intensity, ie the power/area at that distance.
To go from power to momentum you need to work out the number of photons and the momentum of each.
 
mgb_phys said:
100/(4*pi*.05*.05) is the intensity, ie the power/area at that distance.
To go from power to momentum you need to work out the number of photons and the momentum of each.

Why can't I simply divide intensity by the speed of light which would make my units work out?

I submitted my solutions; Pressure = /frac{/frac{100}{4/pi .05^2}}{c} worked.
 
Last edited:
Queue said:
Why can't I simply divide intensity by the speed of light which would make my units work out?

I submitted my solutions; Pressure = /frac{/frac{100}{4/pi .05^2}}{c} worked.

That should be \frac{\frac{100 W}{4pi .05^2 m^2}}{c}

And for some reason this is coming out as mu_0*8/(2*pi*(.0447213595)) for some reason...
 
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