Estimating cot(46°) Using Method of Differentials

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Homework Help Overview

The discussion revolves around estimating cot(46°) using the method of differentials, which some participants relate to linear approximation and Taylor series approximation. The original poster expresses confusion about the method and seeks clarification.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between the method of differentials and linear approximation, with one participant questioning the original poster's familiarity with the method. There is mention of converting degrees to radians to simplify the derivative calculations.

Discussion Status

The conversation is ongoing, with participants providing insights and clarifications. Some guidance has been offered regarding the use of radians and the derivative of cosine, but there is no explicit consensus on the approach to take.

Contextual Notes

The original poster notes confusion stemming from differing terminology in textbooks regarding the method of differentials and linear approximation.

Sethka
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I am completely lost on these differentials! Can anyone help me make sense of them? Especially this question in particular:

cot(46(deg))

(Sorry, I don't know how to make that small little circle thing that denotes degree)

I'm supposed to use the method of differentials to estimate it to 4 decimal places.

Thanks!
 
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Show what you've tried. Do you know how to use this method?

By the way, I'd never heard of the "method of differentials" before, and I had to do a google search to figure out what it is. It seems to just be synonomous with "linear approximation", or, if you want a higher order approximation, "taylor series approximation", by which names I think the method is much more well known. Just another reason to always show your work if you want help.
 
45 degrees is [itex]\frac{\pi}{4}[/itex] radians. 1 degree is [itex]\frac{\pi}{180}[/itex] radians. It's better to use radians because that way the derivative is easier: if x is measured in radians then the derivative of y= cos(x) is y'= -sin(x) and so the differential is dy= -sin(x)dx. y+ dy= cos(x)- sin(x)dx.
To find [itex]cos(\frac{pi}{4}+ \frac{\pi}{180}[/itex], let [itex]x= \frac{\pi}{4}[/itex] so that [itex]y= cos(\frac{\pi}{4})= \frac{\sqrt{2}}{2}[/itex], [itex]-sin(x)= -sin(\frac{\pi}{4})= -\frac{\sqrt{2}}{2}[/itex] and [itex]dx= \frac{\pi}{180}[/itex].
 
Oh Thanks!

Thanks you guys, My textbooks are a little backwards it seems. Where one asks me to use method of differentials the other teaches linear aproximation, that was so confusing and now I see why. Thanks A bunch!
 

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