- #1
DemiMike
- 9
- 0
Use the definiton of the definite inegral (with right hand rule) to evaluate the following integral. Show work please
Can NOT use shortcut method.. but be the long process
1
S (3x^2 - 5x - 6) dx
-4
edit:
i got this so far
1
S (3x^2 - 5x - 6) dx = [3x^3 /3 - 5x^2/2 - 6x], (1, -4)
-4
= 3*1/ 3 - 5*1 /2 - 6*1 - (3*4^3 - 5*4^2 - 6*2)
but iam lost in the simplification
edit: NVm i have no idea how to do the long method.. any 1 help <3 lpz
Can NOT use shortcut method.. but be the long process
1
S (3x^2 - 5x - 6) dx
-4
edit:
i got this so far
1
S (3x^2 - 5x - 6) dx = [3x^3 /3 - 5x^2/2 - 6x], (1, -4)
-4
= 3*1/ 3 - 5*1 /2 - 6*1 - (3*4^3 - 5*4^2 - 6*2)
but iam lost in the simplification
edit: NVm i have no idea how to do the long method.. any 1 help <3 lpz
Last edited: