- #1

DemiMike

- 9

- 0

Use the definiton of the definite inegral (with right hand rule) to evaluate the following integral. Show work please

Can NOT use shortcut method.. but be the long process

1

S (3x^2 - 5x - 6) dx

-4

edit:

i got this so far

1

S (3x^2 - 5x - 6) dx = [3x^3 /3 - 5x^2/2 - 6x], (1, -4)

-4

= 3*1/ 3 - 5*1 /2 - 6*1 - (3*4^3 - 5*4^2 - 6*2)

but iam lost in the simplification

edit: NVm i have no idea how to do the long method.. any 1 help <3 lpz

Can NOT use shortcut method.. but be the long process

1

S (3x^2 - 5x - 6) dx

-4

edit:

i got this so far

1

S (3x^2 - 5x - 6) dx = [3x^3 /3 - 5x^2/2 - 6x], (1, -4)

-4

= 3*1/ 3 - 5*1 /2 - 6*1 - (3*4^3 - 5*4^2 - 6*2)

but iam lost in the simplification

edit: NVm i have no idea how to do the long method.. any 1 help <3 lpz

Last edited: