Evaluate Integral: (1/2(x)^2)(tan^-1x)+(-9cosx)+(x)

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SUMMARY

The integral evaluation discussed involves the expression \(\int \left( \frac{x}{1+x^2} + 9 \sin x + \frac{1}{\ln x} \right) dx\). The solution provided simplifies to \((1/2(x)^2)(\tan^{-1}x) + (-9\cos x) + x\). The first two terms can be integrated using standard techniques, specifically substitution for the first term, while the last term, \(\frac{1}{\ln x}\), does not yield a closed-form solution. This discussion confirms the breakdown of the integral into manageable parts.

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evaluate the integral ((x/1+x^2)+9sinx+(1/lnx))

solution:

integral ((x)(1/1+x^2)+9sinx+(1/lnx))

= (1/2(x)^2)(tan^-1x)+(-9cosx)+(x)


am I close? Thanks!
 
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Is that:

[tex]\int \left( \frac{x}{1+x^2} + 9 \sin x + \frac{1}{\ln x} \right) dx[/tex]

? If so, that's just three questions in one, since you can break it up into the sum of the integrals of the three terms. The first and second are easy (use substitution on the first), but the last doesn't have a nice closed form.
 

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