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Evaluating Indefinite integrals

  1. Feb 7, 2008 #1
    1. The problem statement, all variables and given/known data
    Evaluate

    [tex]\oint x^2 (1-x^3)^6 dx[/tex]

    2. Relevant equations



    3. The attempt at a solution

    let u= 1-x^3
    du= -3x^2
    -1/3 du= x^2 dx
    -1/3 [tex]\oint (u)^6 [/tex]
    = -1/3 (u^7/7)
    = -1/21 (1-x^3)^7 + C

    Is this done correct? I think I followed all the right steps but there is something about it that has me wondering.
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Feb 7, 2008 #2

    HallsofIvy

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    Staff Emeritus
    Science Advisor

    the only problem I see is that circle on your integral symbol!

    What do you get if you differentiate -(1/21)(1-x3)7+ C?
     
  4. Feb 7, 2008 #3
    Yeah, the circle isn't supposed to be there I couldnt find a normal Integration sign.
     
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