Evaluating Indefinite integrals

[n77ler]

Homework Statement

Evaluate

$$\oint x^2 (1-x^3)^6 dx$$

Homework Equations

The Attempt at a Solution

let u= 1-x^3
du= -3x^2
-1/3 du= x^2 dx
-1/3 $$\oint (u)^6$$
= -1/3 (u^7/7)
= -1/21 (1-x^3)^7 + C

Is this done correct? I think I followed all the right steps but there is something about it that has me wondering.

 

[HallsofIvy]

the only problem I see is that circle on your integral symbol!

What do you get if you differentiate -(1/21)(1-x³)⁷+ C?

 

[n77ler]

Yeah, the circle isn't supposed to be there I couldn't find a normal Integration sign.