Evaluating Indefinite integrals

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SUMMARY

The integral evaluation discussed involves the expression \oint x^2 (1-x^3)^6 dx. The solution utilizes the substitution u = 1 - x^3, leading to du = -3x^2 dx and -1/3 du = x^2 dx. The final result is -1/21 (1-x^3)^7 + C, although the presence of the circular integral symbol is noted as incorrect. The differentiation of the result confirms the correctness of the integration steps taken.

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  • Understanding of indefinite integrals and integration techniques
  • Familiarity with substitution methods in calculus
  • Knowledge of differentiation to verify integration results
  • Basic algebraic manipulation skills
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  • Study integration techniques, focusing on substitution methods
  • Learn about the properties and applications of definite and indefinite integrals
  • Practice differentiation to confirm integration results
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Students studying calculus, particularly those focusing on integration techniques, and educators looking to clarify common integration errors.

n77ler
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Homework Statement


Evaluate

\oint x^2 (1-x^3)^6 dx

Homework Equations





The Attempt at a Solution



let u= 1-x^3
du= -3x^2
-1/3 du= x^2 dx
-1/3 \oint (u)^6
= -1/3 (u^7/7)
= -1/21 (1-x^3)^7 + C

Is this done correct? I think I followed all the right steps but there is something about it that has me wondering.
 
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the only problem I see is that circle on your integral symbol!

What do you get if you differentiate -(1/21)(1-x3)7+ C?
 
Yeah, the circle isn't supposed to be there I couldn't find a normal Integration sign.
 

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