Evaluating Integral: $\int_0^{\pi/2} \frac{1}{y+\cos x}dx$

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SUMMARY

The integral $\int_0^{\pi/2} \frac{1}{y+\cos x}dx$ can be evaluated by treating \( y \) as a constant during integration. The result will yield a definite integral that remains dependent on \( y \), producing different outcomes for various values of \( y \). The substitution \( t = \tan(x/2) \) is a valid approach to simplify the evaluation process. This method allows for a clearer understanding of how the integral behaves as a function of \( y \).

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RYANDTRAVERS
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How do you evaluate an integral such as:
\begin{equation}
\int_0^\frac{\pi}{2} \frac{1}{y+cosx} \, dx
\end{equation}
I was thinking whether to treat y as a constant and then integrate as such and be left with an arbitrary constant that is a function of y. This constant, f(y), should then disappear when evaluating the definite integral...?
 
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That depends on what you want to find out. Does y have some fixed relationship to x?
Usually, y will be a constant, and the definite integral will still depend on y in the same way the integral will give different results if you replace y by different real numbers.
 
I’ve attached my attempt at the question. Just wanted to know what you think? I’ve got a definite integral that is a function of y, I(y), and have used the substitution t=tan(x/2).
 

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