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Not so much a homework problem as a curiosity on my part. I chose to give a presentation recently on undefined numbers. With that, indeterminate's unsurprisingly found their way into my presentation.
After reading up on the list of indeterminate forms, I stumbled upon the form 0^\infty and for the life of my couldn't think of any examples in limits that have this form.
In my mind, I see such indeterminates as 1^\infty as trying to say
"multiplying 1 by itself repeatedly obviously still gives 1, but we're trying to do it so many times that it finally equals something other than 1".
Such an example would be e:
\lim_{x\rightarrow \infty}\left(1+\frac{1}{x}\right)^{x}
Now a quick example of 0^\infty would be \lim_{x\rightarrow \infty}\left(\frac{1}{x}\right)^x
but in a way, I see this as "enforcing" the answer zero since this limit tends to zero much faster than \lim_{x\rightarrow \infty}\frac{1}{x} does.
So can anyone give me an example of such an indeterminate form that equals a finite, and possibly even infinite value.
After reading up on the list of indeterminate forms, I stumbled upon the form 0^\infty and for the life of my couldn't think of any examples in limits that have this form.
In my mind, I see such indeterminates as 1^\infty as trying to say
"multiplying 1 by itself repeatedly obviously still gives 1, but we're trying to do it so many times that it finally equals something other than 1".
Such an example would be e:
\lim_{x\rightarrow \infty}\left(1+\frac{1}{x}\right)^{x}
Now a quick example of 0^\infty would be \lim_{x\rightarrow \infty}\left(\frac{1}{x}\right)^x
but in a way, I see this as "enforcing" the answer zero since this limit tends to zero much faster than \lim_{x\rightarrow \infty}\frac{1}{x} does.
So can anyone give me an example of such an indeterminate form that equals a finite, and possibly even infinite value.