Existence and Uniqueness theorem for 1st order ODEs

Silversonic
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Homework Statement



Consider the IVP compromising the ODE.

dy/dx = sin(y)

subject to the initial condition y(X) = Y

Without solving the problem, decide if this initial value problem is guaranteed to have a unique solution. If it does, determine whether the existence of that solution is guaranteed for all values of x.

I'm not sure how to answer this. f(x,y) and df(x,y)/dy are both continuous for all values of x and y. This means there is exactly one solution to the IVP.

Now working out what the solution is, we get;

In(1-cos(y)/sin(y)) = x + C.

What I don't get is whether it's guaranteed for all values of x? I don't believe it is, as because if x < -C then we get a negative number on the RHS. This is not computable. HOWEVER, if I'm right, how was I meant to work that out without working out the solution?

I also need to check that I'm correct in saying that that existence of a unique solution is guaranteed.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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