Expected Value of Distribution on Histogram: T/F

AI Thread Summary
The expected value of a distribution does not always occur at the center of the tallest bar on a histogram, making the statement false. To illustrate this, one can create a histogram and calculate the mean value to see if it aligns with the highest bar. This approach can be easily executed using software like Matlab or even by hand. The discussion emphasizes the importance of testing the hypothesis through practical examples. Ultimately, the expected value can vary and is not strictly tied to the tallest bar in the histogram.
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Homework Statement



4: (T/F) The expected value of a distribution always occurs at the center of the tallest bar on the histogram.

Homework Equations



(no equation necessary for it is T/F)

The Attempt at a Solution



I believe this is false for the expected value can be definite or indefinite.
 
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If you believe it is false, why don't you make a simple histogram that illustrates that it isn't true? That would settle it and you wouldn't be guessing.
 
Yup, just make up a histogram and test it.
Easy as pie in Matlab, or even just by hand.

-> The thing to do is calculate the mean value of the histogram, and check if that is in the "highest bar".
 

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