Experimental work to prove that the Drag Coefficient of a sphere is 0.5

AI Thread Summary
Experiments to prove the drag coefficient of a sphere being approximately 0.5 can include using a wind tunnel or levitating the sphere in a vertical tube to measure its terminal velocity. Dropping the sphere from a height and precisely timing its fall can also provide data for comparison against calculated fall times with and without drag. Access to a wind tunnel is confirmed, and the focus is on measuring drag force accurately. Suggestions include using strain gauges and pitot tubes to measure flow velocity and calculate momentum change to derive the drag force. These methods aim to validate the theoretical drag coefficient of 0.5 for a sphere.
daniscp
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Is there any experiments I could do to prove that the Drag Coefficient of a Sphere is more or less 0.5 depending on the roughness of the sphere?
 
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The obvious question- do you have access to a wind tunnel?

Other than that, it might be possible to levitate the sphere in a vertical tube with air blowing through at its terminal velocity, or perhaps drop the sphere a long distance and measure its fall time very precisely, and compare that time to a calculated fall times with and without drag?
 
I recognize your name now... Isn't this basically a repost of your previous thread?
 
Mech_Engineer said:
The obvious question- do you have access to a wind tunnel?

Other than that, it might be possible to levitate the sphere in a vertical tube with air blowing through at its terminal velocity, or perhaps drop the sphere a long distance and measure its fall time very precisely, and compare that time to a calculated fall times with and without drag?

Yeah I have access to a wind tunnel...

It's not a repost since I've decided now to focus on proving that the drag coefficient of a sphere is 0.5. The only thing I need to think of is an experiment to measure the drag force...but can't come up with one :mad:
 
How about some strain gauges?
 
You can measure the flow velocity behind the ball using a pitot at several locations that you can calculate the momentum change which is equal to the drag force so you divide that by D*rho*V^2*0.5 and you will probably get a value near 0.5 (plus or minus 0.5).
 
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