erobz
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Lets assume that the flow in the control volume is uniformly distributed, and experiences a constant acceleration along the circular arc ##s##.
In other words ##\ddot s = k## implies:
$$ \frac{d \dot s }{d \theta} \frac{d \theta }{dt} = k $$
Since ## \dot s = r \dot \theta ##:
$$ \frac{d \dot s }{d \theta} \frac{\dot s }{r} = k $$
Separate variables, integrate this over ##\theta##, with ## \dot s = V## implies that the scalar velocity of the flow along at any point along the arc is given by:
$$ V = \sqrt{2kr \theta + V_1^2} $$
Does anyone have complaints about the "lever pulling" I'm about to do for fear of basic representation of the unsteady terms in the Mass Continuity/ Energy equations before I go further?
I believe I can get the pressure ##P_2## at the outlet as function of ## V_1, \dot V_1, k ## etc... (the velocity of the cart, cart acceleration, etc... ). Explicitly I'm not sure, but at least implicitly it looks like I have it.
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