Explain this to me as if I were 5 years old

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Homework Statement



5.10. Definition. A permutation of a finite set S is a bijection from S to itself. The word form of a permutation of [n] is the list obtained by writing the image of i in position i. We write n!, read as "n factorial", to mean n*(n-1)*(n-2)* ... *2*1.


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The Attempt at a Solution



Please explain the mumbo jumbo before the last sentence.
 
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For example, a permutation of the set {1,2,3} could be a function f(x) where f(1)=1, f(2)=3 and f(3)=2. By the word form we can write this permutation as 1 3 2. The number 1 is first so f(1)=1. The number 3 is second so f(2)=3. The number 2 is third so f(3)=2 (permutations are rarely denoted as f(x) but I do so here for the sake of clarity)

If you were given the permutation f(x) described by 2 5 3 4 1, then f(1)=2 since the first number listed is a 2, and f(2)=5 since the second number listed is a 5
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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