Explain why this function is discontinuous

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Homework Help Overview

The discussion revolves around a piecewise function and its continuity at a specific point, x = -1. Participants are tasked with explaining the discontinuity of the function using the test for continuity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the existence of the function and its limit at the point of interest, with attempts to factor the function and evaluate limits. Questions arise regarding the correctness of the limit values provided in the textbook.

Discussion Status

The discussion is ongoing, with participants expressing uncertainty about the textbook's answers and questioning the accuracy of their own calculations. Some participants suggest that the textbook may contain errors, while others are attempting to clarify their understanding of the function's behavior at the discontinuity.

Contextual Notes

There is a focus on the piecewise nature of the function and the specific limit evaluations at x = -1. Participants are navigating conflicting information regarding the limits and continuity from the textbook.

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Homework Statement


Using the test for continuity at a point, explain why each function is discontinuous at the given x-value. Classify each discontinuity.

the question is a piecewise function.

i(x)={(x^2+5x+4)/(x^3+1), x=/= -1
{2, x=-1

this is all one piece wise function.


The Attempt at a Solution



I first can say that the function exists and the limit exists just by glance. At x=-1 for the first piece, it is indeterminent. So I factor the first piece and end up with:

lim (x+4)/(x^2+x+1)
x->-1

subbing in a negative one I get 3.

but the back of the book says:

lim i(x) =2
x->-1

I'm not sure how.
 
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you should get x^2-x+1 and not x^2+x+1. But I get 1 instead of 2 still...
 
nvm, the book must be wrong..
 
Well, for one thing you factored the denominator wrong. Are you sure the back of the book doesn't say lim(i(x))=1 as x->-1?
 
I think the book's wrong seeing as it wants you to show why the function is not continuous, when its answer would actually show that it is continuous at x=1... I think rock freak is right on this one.
 

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