maali5
- 35
- 0
Homework Statement
The following data has been collected:
Gas volume: V = 0.8 m3
Gas pressure: p = 160 kPa
Compression index: n = 1.4
Pressure/volume relationship: pV^n = C
Work done = ∫ TOP=V2 BOTTOM =V1
You first need to work out C, the value of the pressure/volume relationship.
Calculate the work done in compressing the nitrogen from 0.8 m3 to 0.6 m3 using:
integral calculus Simpson’s rule
Comment on the accuracy of the numerical method.
Note: if you wish, you may use a spreadsheet for the numerical method.
3. The Attempt at a Solution
As i did not understand the question, I copied out all the work from a classmate. Would you please explain to me what is going on please.
ThanksPart 1
Integral calculus:
pV^1.4=C so p=C/V^1.4.
Work done ON the gas = -∫p dV = C∫ (1/V)^1.4 dV
= -C [ 1/(-1.4+1)][V^(-1.4+1)]
= -C [ 1/(-0.4][V^(-0.4)]
= +2.5C (1/V2^0.4 - 1/V1^0.4)
V1=0.8, V2=0.6, C=p1V1^1.4=160000*0.8^1.4=117070.
work done = +2.5*117070*(1/0.6^0.4 - 1/0.8^0.4) = +39025 J = +39.0 kJ.
Part 2: Simpson rule - I have attached an excel file I basically don't understand how "group c" includes this formula
This formula being "(117.07*10^3)/(number^1.4) "
for 1= 0.8 =(117.07*10^3)/(0.8^1.4) = 159999,8725
2=0.775 =(117.07*10^3)/(0.775^1.4) =167271,9943
etc
Thank you very much