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## Main Question or Discussion Point

A falling object with no initial velocity with mass m is influenced by a gravitational force g and the air resistance which is proportional to the object´s speed. By Newton´s laws this can be written as:

(1) mg-kv=ma or (2) mg-kv^2=ma (for large velocities).

I assume that k is a positive constant that depends on the geometry of the object and the viscosity. But how can one explain that the air resistance is proportional to the velocity? And to the velocity squared in the second equation?

(1) mg-kv=ma or (2) mg-kv^2=ma (for large velocities).

I assume that k is a positive constant that depends on the geometry of the object and the viscosity. But how can one explain that the air resistance is proportional to the velocity? And to the velocity squared in the second equation?