I Exponential Distribution Question

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The life expectancy of a tiger is modeled by an exponential distribution with a mean of 15 years. Given that a tiger is currently 10 years old, the expected remaining life is 5 years, demonstrating the property of memorylessness. Memorylessness means that the probability distribution of the remaining time until an event occurs remains constant, regardless of the time already elapsed. This property is characteristic of only two distributions: the exponential and the geometric distributions. Understanding this concept is crucial for accurately interpreting expectations in probabilistic scenarios.
Caution
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Hi all,
Can anyone teach me this problem ? Thanks

The life of a tiger is exponentially distributed with a mean of 15 years.If a tiger is 10 years old, what is the expected remaining life of the tiger?

A 5 years
B 10 years
C 15 years
D Longer than 15 years
 
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Can you tell me your understanding of 'memorylessness'? What distributions have this property and what does it mean?
 
StoneTemplePython said:
Can you tell me your understanding of 'memorylessness'? What distributions have this property and what does it mean?

It means the probability distribution of the remaining time until the event occurs always is the same, regardless of how much time (s) already has passed. So I'm guessing the answer is 5?
 
Caution said:
It means the probability distribution of the remaining time until the event occurs always is the same, regardless of how much time (s) already has passed. So I'm guessing the answer is 5?

so if the probability distribution is the same whether 0 years have passed or 7 years have passed, then what does that tell you about forward looking expectations?

Also do you know which distributions exhibit memorylessness? (There are only 2...)
 
I was reading a Bachelor thesis on Peano Arithmetic (PA). PA has the following axioms (not including the induction schema): $$\begin{align} & (A1) ~~~~ \forall x \neg (x + 1 = 0) \nonumber \\ & (A2) ~~~~ \forall xy (x + 1 =y + 1 \to x = y) \nonumber \\ & (A3) ~~~~ \forall x (x + 0 = x) \nonumber \\ & (A4) ~~~~ \forall xy (x + (y +1) = (x + y ) + 1) \nonumber \\ & (A5) ~~~~ \forall x (x \cdot 0 = 0) \nonumber \\ & (A6) ~~~~ \forall xy (x \cdot (y + 1) = (x \cdot y) + x) \nonumber...

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