Sam Anderson
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Could somebody at least tell me about mods in exponents?
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Sam Anderson said:Let 3^n denote 333... (n+1 threes in total)
Thanks for the quick reply, but I wasn't finished typing. I accidentally hit enter. Sorry.Mentallic said:Tetration already has a formalized expression.
^n3=3^{3^{...^3}} with n 3's in the stack.
Or you can even use Knuth's up arrow notation. Exponentiation is denoted by 1 up arrow, and tetration by 2, so
^n3 = 3\uparrow\uparrow n
So what's your question?
Sam Anderson said:Could somebody at least tell me about mods in exponents?