- #1
Ry122
- 565
- 2
How do I express the following in the form a+ib?
[tex] (\sqrt{-4} - 1) (\sqrt{-9}) [/tex]
My attempt:
(2i - 1)(3i)
6i-3i = 3i
[tex] (\sqrt{-4} - 1) (\sqrt{-9}) [/tex]
My attempt:
(2i - 1)(3i)
6i-3i = 3i
Last edited:
What was that the answer to?? Surely not the (2i-1)(3i) problem you were just talking about!Ry122 said:Can you tell me why the answer -6-+3i has plus or minus 3i?
The answer to a2- a2 is 0 no matter what a is!Also can you tell me the answer to (3+i)^2 - (3+i)^2
The answer I got was 0.
9+6i+i^2-9-6i-i^2=0
A complex number is a number that contains both a real part and an imaginary part, and can be expressed in the form a + bi, where a is the real part and bi is the imaginary part, with i representing the square root of -1.
Complex numbers are used to represent quantities that involve both real and imaginary components, such as electrical currents or waves. They also have many applications in mathematics, physics, and engineering.
The real part of a complex number represents the horizontal axis on the complex plane, while the imaginary part represents the vertical axis. The real part is a normal number, while the imaginary part is a multiple of the imaginary unit i.
A complex number can be expressed in polar form as r(cosθ + isinθ), where r is the modulus (or magnitude) of the complex number and θ is the angle between the positive real axis and the vector representing the complex number on the complex plane.
Yes, complex numbers can be added, subtracted, multiplied, and divided using the same rules as real numbers, with the added step of combining like terms of i. For division, the complex conjugate of the denominator is multiplied to eliminate the imaginary part in the denominator.