Extend Vector to Orthogonal Basis

special-g
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How do you extend a vector (let's use vector (1,2,3) for example) to an orthogonal basis for R^3?
 
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special-g said:
How do you extend a vector (let's use vector (1,2,3) for example) to an orthogonal basis for R^3?

First find a vector perpendicular to (1,2,3). That's not hard if you think about the dot product. Any one, there are many. Then find a vector perpendicular to the first two. That's easy in R^3 if you use the cross product. There is no unique answer, you know.
 
Thanks, that helps quite a bit...we just started this material and there aren't very many examples in the book to go off of. :)

I don't know if I did this completely right because I haven't taken calc 3 in a while.

For the first vector, would this be one answer: vector (-5, 1, 1) after taking the dot product.
Then, after taking the cross product of those two vectors, I got vector (-1,-16,11).
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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