javiergra24
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Homework Statement
Suppose a relativistic particle with spin 1/2 at rest. Show that if we apply an electrical field at t=0 there's a probability fot t>0 of finding the particle in a negative energy state if such negative energy states are assumed to be originally empty.
Homework Equations
Dirac equation at rest:
<br /> (\boldsymbol{\hat{\beta}} mc^2) \psi (\mathbf{x},t) = i \hbar \frac{\partial\psi(\mathbf{x},t) }{\partial t}<br />
Spinor solutions with positive energy for t<0
<br /> $\Psi_{+}=\begin{pmatrix}<br /> \psi^{(1)}\\ \psi^{(2)}<br /> \end{pmatrix}={1\over\sqrt{V}}\begin{pmatrix}<br /> 1\\ 1\\ 0\\ 0<br /> \end{pmatrix}e^{-imc^2t/\hbar}$\\<br /> <br />
Applied electrical field and consecuent magnetic potential
<br /> $\mathbf{E}=E_0 \cos(\omega t)\mathbf{u}_{x} \qquad \mathbf{A}=-\frac{E_0}{\omega} \sin(\omega t)\mathbf{u}_{x}$<br />
The Attempt at a Solution
I'm not sure how to solve this problem. Is it supposed that the particle at t>0 remains at rest? Or it has a negative energy E'?. First order perturbation theory must be used, but how about the final state of the particle?
Perturbed Hamiltonian should be
<br /> $\displaystyle H'(t)=q c \boldsymbol{\hat{\alpha}} \mathbf{A}=q c\hat{\alpha}_{x}A_{x}$<br />
Is it correct?
Thank you
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