Extremely frustrated - inclined plane problem w/ friction

AI Thread Summary
The discussion revolves around solving a physics problem involving two masses on an inclined plane with friction. For mass M1 (6.58 kg) on a 59-degree incline with a coefficient of kinetic friction of 0.18, the user is attempting to calculate the acceleration for two scenarios: M1 moving up and M1 moving down the incline. The user correctly identifies the forces acting on M1 and sets up equations for both cases, incorporating friction and gravitational components. Clarification is sought on the approach and the direction of acceleration in both scenarios. The thread emphasizes the importance of correctly defining the positive direction for acceleration in the calculations.
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Homework Statement


Mass M1 (6.58 kg) is on a rough inclined plane that makes an angle θ = 59o with the horizontal. The coefficient of kinetic friction between M1 and the incline is μk = 0.18. A rope is attached to M1, passes over a frictionless pulley, and is attached to mass M2 = 7.30 kg which hangs freely.
(a) If M1 is initially moving up the incline: find the magnitude of the acceleration of the masses.
(b) If M1 is initially moving down the incline: find the magnitude of the acceleration of the masses.


Homework Equations


Frictional force = μk * N
F=mg
Components


The Attempt at a Solution


I drew the inclined plane and labeled all of the forces. To solve part (a), M1 is moving up the incline, making the frictional force in the direction of the bottom of the plane, parallel to the plane. The total frictional force should be (μ*N) + (mg*sin(59)), if I am correct. The net force on M1 would be (M2*g) - [(μ*N) + (mg*sin(59))] = (Ʃm)*a

We then divide by Ʃm to get the acceleration.

For part (b), it's the same idea. I would solve it like this:

(mg*sin(59)) - [(M2*g) + (μ*N)] = (Ʃm)*a

We divide by Ʃm again to find the acceleration.

Am I taking the wrong approach? Also, if I'm not being clear on any part, let me know.
 
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If you mean M1 on m your equations are correct. Explain the chosen direction of acceleration in both cases, what direction you take positive.

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