F[a][b] vs F[a,b]: What's the Difference?

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What is F[a]?

I'm having a hard time with notation. If F[x] is the set of polynomials in x, then what is:

F[a]?

How is it different from F[a,b]?


And help would be great?
 
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futurebird said:
I'm having a hard time with notation. If F[x] is the set of polynomials in x, then what is:

F[a]?

How is it different from F[a,b]? And help would be great?

The very pleasant thing is that F[a,b] really is isomorphic to F[a], just like we want it to be!
 


Hurkyl said:
The very pleasant thing is that F[a,b] really is isomorphic to F[a], just like we want it to be!


Great! But what the heck are they? :-p
 


futurebird said:
Great! But what the heck are they? :-p
F[a] is the set of polynomials in b whose coefficients are elements of F[a]
F[a,b] is the set of bivariate polynomials in a and b whose coefficients are elements of F
 


Hurkyl said:
F[a] is the set of polynomials in b whose coefficients are elements of F[a]


Oh that makes sense-- it's sort of recursive... OK. God my book is so muddled and just starts talking about F[a] out of the blue like it's clear what that would mean.

Thank you so much no I can keep studying!

:rolleyes:
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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