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F=ma applied to slider crank piston motion

  1. Feb 4, 2012 #1
    I'm struggling to apply F=ma to the motion of a slider crank, more specifically the piston. I want to find out how much force is nessesary to keep the piston in motion. Essentially, in the mechanism there is acceleration and deceleration, does that mean only at some points in the cycle there is force needed to move the piston?

    Using the equations derived for the motion of a piston:

    http://upload.wikimedia.org/wikipedia/en/math/1/6/8/1686ee2f8b1d67ce1eb1aa4fb4b0daac.png [Broken]

    9b2e87b937f4942da5b81113ade86f0e.png

    29bde840b3d4c0a03708f2d941f33a54.png

    Gives you this:

    800px-Graph_of_Piston_Motion.png
     
    Last edited by a moderator: May 5, 2017
  2. jcsd
  3. Feb 4, 2012 #2
    Sorry, I should add why I'm asking this. I have the following diagram:

    0klgQ.jpg

    Where f_g is the combustion force, f_j is the inertial force and f is the resultant force. I'm trying to work out whats providing the force to overcome the acceleration around 650 to 90 degrees.
     
  4. Feb 4, 2012 #3

    256bits

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    Gold Member

    shaft flywheel
     
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