F=ma applied to slider crank piston motion

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SUMMARY

The discussion focuses on applying Newton's second law, F=ma, to analyze the motion of a slider crank mechanism, specifically regarding the piston. The user seeks to determine the necessary force to maintain piston motion, particularly during acceleration and deceleration phases. Key forces involved include combustion force (f_g), inertial force (f_j), and resultant force (f). The user is particularly interested in the forces acting between 650 to 90 degrees of the crankshaft's rotation.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Familiarity with slider crank mechanisms
  • Knowledge of forces acting on pistons in mechanical systems
  • Basic proficiency in interpreting mechanical diagrams
NEXT STEPS
  • Study the dynamics of slider crank mechanisms in detail
  • Learn about the calculation of combustion and inertial forces in piston motion
  • Research the effects of crankshaft angles on force requirements
  • Explore simulation tools for analyzing mechanical motion, such as MATLAB or Simulink
USEFUL FOR

Mechanical engineers, students studying dynamics, and anyone involved in the design or analysis of piston-driven mechanisms will benefit from this discussion.

Kalus
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I'm struggling to apply F=ma to the motion of a slider crank, more specifically the piston. I want to find out how much force is nessesary to keep the piston in motion. Essentially, in the mechanism there is acceleration and deceleration, does that mean only at some points in the cycle there is force needed to move the piston?

Using the equations derived for the motion of a piston:

http://upload.wikimedia.org/wikipedia/en/math/1/6/8/1686ee2f8b1d67ce1eb1aa4fb4b0daac.png

9b2e87b937f4942da5b81113ade86f0e.png


29bde840b3d4c0a03708f2d941f33a54.png


Gives you this:

800px-Graph_of_Piston_Motion.png
 
Last edited by a moderator:
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Sorry, I should add why I'm asking this. I have the following diagram:

0klgQ.jpg


Where f_g is the combustion force, f_j is the inertial force and f is the resultant force. I'm trying to work out what's providing the force to overcome the acceleration around 650 to 90 degrees.
 
shaft flywheel
 

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