F non-measurable but |f| and f^2 are

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Homework Statement



Find a function in a measurable space that is non-measurable, but |f| and f2 are measurable.

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The Attempt at a Solution



I am trying to understand the following answer to the problem:

MMx7fFs.png

(source: http://math.stackexchange.com/a/1233792/413398)

I do not understand why for all subsets S \subseteq \mathbb{R}, we have $$(|f|)^{-1}(S)=(f^2)^{-1}(S)=X \text{ or } \varnothing$$
 
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Hi,

##f^2## or ##abs(f)## both send ##a## and ##b## to ##1##. So ##1## has ##a## and ##b## as antecedents, and any other real has no antecedent. So if ##S## contains ##1## it has ##X=\{a,b\}## as reciprocal image, and the empty set if it doesn't contain it.
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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