Factoring a polynomial where factor theorem doesn't work

adrimare
Messages
33
Reaction score
0

Homework Statement



Solve: x^3 - 9x^2 + 15x + 30

Homework Equations





The Attempt at a Solution



The factors of 30 are +-1, +-2, +-3, +-5, +-6, +-10, +-15, and +-30.

I used my graphing calculator and got a zero close to -1. I plugged it into the original equation and got 5, not 0. I used the zero function on my calculator and found that the zero occurred around -1.13. that's a fraction.

How would I solve this algebraically?
 
Physics news on Phys.org
Try Newtons method:
Define
T(x)=x-\frac{f(x)}{f'x}=x-\frac{x^3-9x^2+15x+30}{3x^2+18x+15}
 
If you are only looking for a numerical approximation, then Newton's method should work fine for you. However, if you are looking for an exact analytical solution, try the cubic formula
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top