Factorization of rings problem

zetafunction
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Homework Statement



in order to factorize 20 on the rings of Q( \sqrt 2) i must solve

Homework Equations



x^{2} -2y^{2}=10

The Attempt at a Solution



i do not know how to solve it, i have tried by brute force with calculator but can not get any response , the given hint is that x^{2} -2y^{2}=5 has no solution.
 
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I can only guess that you've factored 20 as 2*10, so why have you not factored 10 as 2*5?
 


according to the teacher, who put the exercise the diophantine equation

x^{2}-2y^{2}=5 has no solution on integers.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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