- #1
blue5t1053
- 23
- 1
Problem:
A rigid assembly is made of a light weight rod 2 m long and a heavy gold ball which is attached at the middle of the rod. The rigid assembly initially rests with one end on the ground in a vertical position. If released what speed does the top of the rod have when it strikes the ground?
Equations:
[tex]Rotational \ Inertia \ for \ a \ thin \ rod \ about \ central \ axis; \ \ I = \frac{1}{12} M L^{2}[/tex]
[tex]Rotational \ Inertia \ for \ a \ thin \ rod \ about \ non-central \ axis; \ \ I = \frac{1}{12} M L^{2} + M R(from \ center)^{2}[/tex]
[tex]Rotational \ Inertia \ for \ a \ sphere; \ \ I = \frac{2}{5} M r^{2}[/tex]
My Work:
Any help where to start? I am lost. I know that the final answer is 8.85 m/s.
A rigid assembly is made of a light weight rod 2 m long and a heavy gold ball which is attached at the middle of the rod. The rigid assembly initially rests with one end on the ground in a vertical position. If released what speed does the top of the rod have when it strikes the ground?
Equations:
[tex]Rotational \ Inertia \ for \ a \ thin \ rod \ about \ central \ axis; \ \ I = \frac{1}{12} M L^{2}[/tex]
[tex]Rotational \ Inertia \ for \ a \ thin \ rod \ about \ non-central \ axis; \ \ I = \frac{1}{12} M L^{2} + M R(from \ center)^{2}[/tex]
[tex]Rotational \ Inertia \ for \ a \ sphere; \ \ I = \frac{2}{5} M r^{2}[/tex]
My Work:
Any help where to start? I am lost. I know that the final answer is 8.85 m/s.