Faraday rotation and permittivity tensor

AI Thread Summary
The discussion centers on the role of the Hermitian permittivity tensor in understanding Faraday rotation in magneto-optic materials. It questions whether knowledge of the tensor alone is sufficient to solve the wave equation and calculate wave propagation, including polarization rotation. The conversation highlights the complexity of breaking linearly polarized light into circularly polarized components, suggesting that while the tensor provides essential information, additional methods may be needed for practical calculations. It concludes that solving the eigenvalue problem for the permittivity tensor can yield the necessary solutions for left and right circularly polarized waves. Understanding this process is crucial for accurate predictions of wave behavior in these materials.
Hassan2
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Dear all,

In textbooks about optics in magneto-optic materials, we often come across a Hermitian permittivity tensor with off-diagonal imaginary components. These components are relevant to the Faraday rotation of plane of polarization of light through the material.

Now my question is: Is the knowledge of the tensor enough to solve the wave equation and calculate the wave propagation ( including rotation)?

I ask this because they usually talk about breaking the incident linearly polarized light into left and right circularly polarized lights, where the refractive index is different for each. if the knowledge of permittivity tensor is enough for the calculations, why would we need such a non-easy-to-understand trick?

Your help is highly appreciated.
 
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The point is that the wave equation with the permittivity being a tensor depending on wavenumber has two solutions (for given direction of the k vector and frequency) which turn out to correspond to left and right circularly polarized waves. Basically, you have to find a basis where the permittivity tensor is diagonal. This is a matrix eigenvalue problem which you can solve with the usual methods.
 
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Very clear.Thanks.
 
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