beanus
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Homework Statement
A coil 3.55 cm radius, containing 480 turns, is placed in a uniform magnetic field that varies with time according to B = (1.20e-2 T/S)t + (3.05e-5 T/s^{4} )t^{4}. The coil is connected to a 620 Ohm resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.
Homework Equations
\Phi_{B}=BA
ε = - \frac{\Phi_{B}}{t}
The Attempt at a Solution
First I divided by t and removed a t from each term in "B"
r = .0355
N = 480
A = \pi(.0355)^{2} = 3.959192142e-3
AN = (3.959192142e-3)(480) = 1.900412228
So all we're left with is:
BAN = 1.900412228 [(1.20e-2 T/S) + (3.05e-5 T/s^{3} )t^{4}]
ε = (2.28e-2 V) + (5.80e-5 V/s^{3})t^{3} should be my final answer but mastering physics says I'm wrong. Please help thanks!
EDIT:
I just found a posting where they multiplied the second term in B (3.05e-5 T/s^{3} )t^{4} by 4. When I did that I got the correct answer! But I don't know why I would multiply the term by 4. Any thoughts?
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