Faraday's law with loop of wire and resistor

AI Thread Summary
A coil with a radius of 3.65 cm and 560 turns is subjected to a time-varying magnetic field, resulting in an induced emf expressed as E= 2.81×10^−2 V +( 2.86×10^−4 V/s^3)t^3. The coil is connected to a 600-Ω resistor, and the current needs to be calculated at t0 = 4.50 s. The discussion highlights the importance of considering the number of turns in the emf calculation and suggests incorporating self-inductance into the analysis. Despite obtaining the correct emf, the user encounters difficulties in calculating the current. Understanding the relationship between induced emf, resistance, and self-inductance is crucial for accurate results.
xSpartanCx
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A coil 3.65 cm radius, containing 560 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×10^−2 T/s)t+( 3.05×10^−5 T/s4)t^4. The coil is connected to a 600-Ω resistor, and its plane is perpendicular to the magnetic field. You can ignore the resistance of the coil.
What is the current in the resistor at time t0 = 4.50 s ?I got the correct induced emf value:
E= 2.81×10^−2 V +( 2.86×10^−4 V/s3 )t^3

I've tried plugging in 4.5s into the emf equation and then dividing I = V/R but the answer is incorrect.
 
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xSpartanCx said:
I got the correct induced emf value:
E= 2.81×10^−2 V +( 2.86×10^−4 V/s3 )t^3
Did you multiply it by the no of turns(560)?
 
cnh1995 said:
Did you multiply it by the no of turns(560)?
Yes, that's part of the emf value.
 
Has your course covered self-inductance?
Perhaps you're expected to include the factor E = - L di / dt.
 
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