Fermi Energy of 40P 50N Nucleus Sphere

AI Thread Summary
To calculate the Fermi energy for a nucleus with 40 protons and 50 neutrons, the relevant formula is EF = ((h-bar)^2*(3*pi^2*n)^(2/3))/2m, where m is the mass of the fermions involved. The number density n can be determined using n = N/V, where N is the total number of nucleons and V is the volume of the spherical nucleus, calculated from its radius of 4.6 x 10^(-15) m. The mass used in the calculation should be that of the nucleons (protons and neutrons), not electrons, as they are the relevant fermions in this context. The discussion emphasizes the importance of correctly identifying the mass and number density of the particles when applying the Fermi energy formula.
viviane363
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Homework Statement


I am wondering about something:
Calculate the Fermi energy for the neutrons confined to a nucleus with 40 protons and 50 neutrons which roughly forms a sphere of radius 4.6 10^(-15) m.


Homework Equations


the formula of the fermi Energy is EF= ((h-bar)^2*(3*pi^2*n)^(2/3))/2m
m:mass of electron, n = number density of electron


The Attempt at a Solution


Then, in the problem we are given protons and neutrons. Where does influence the formula? and where do we use the radius there is one relation that is n = N/V ( N= protons+Neutrons)
and V is the volume of the sphere.
is it right?
Also, do we use the mass of electron or the mass of proton = neutron this time?
 
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The mass should be of fermions in general - not just electrons. Same with the number density. And since protons and neutrons are fermions, you're equation should work.
 
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