Fibonacci Proof with Induction

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I'm working on a question as stated above for my computer science course. Since the topic was taken the Fibonacci numbers have puzzled me with their laws for simplification etc...

Here is the question:
http://img404.imageshack.us/img404/7668/fib0au.png

I'm not sure where to start with it whether I should use standard induction or strong induction to prove it.

Any help would be apreciated.

PS if this is in the wrong place then move it.

-Shane
 
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Well, start it and then decide whether to use regular or strong induction. Whichever you use, you will need to prove the "base" case:
with n= 1 you want to show that f32- f2[/sup]2= f1f4. Of course, f1= 1,f2= 1, f3= 2, f4= 3 so that just says
22- 12= 1*3 which is true.
Since that involves numbers less than just n-1, "strong induction" will probably work better. Assume that fk+22- fk+12= fkfk+3 for some k. Then we need to show that fk+32- fk+22= fk+1fk+4. By definition of Fibonacci sequence, fk+4= fk+2+ fk+1, fk+3= fk+1+ fk+2, fk+2= fk+ fk+1, fk+1= fk+ fk+1 so try putting those in.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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