Fields & Potential Homework Solutions

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SUMMARY

The discussion focuses on calculating the electric field and potential difference due to a point charge at the origin, with the electric field defined as E=(6.00 kVm/x²)i. The magnitude of the point charge is determined to be approximately 6.67 x 10^-7 C using the formula q = a/k, where k is the Coulomb's constant. The potential difference between points on the x-axis at x=1 m and x=2 m is to be calculated using the equation Vb-Va=-∫Edl. The potential energy of a proton at these positions remains uncalculated.

PREREQUISITES
  • Understanding of electric fields and point charges
  • Familiarity with Coulomb's law (E=kq/r²)
  • Knowledge of electric potential and potential difference
  • Ability to perform definite integrals in the context of physics
NEXT STEPS
  • Calculate the potential difference using the integral Vb-Va=-∫(6.00 kVm/x²)dx from x=1 to x=2
  • Explore the concept of electric potential energy for charged particles
  • Investigate the direction of electric fields relative to point charges
  • Review the application of integration in physics problems involving electric fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone looking to deepen their understanding of electric fields and potential differences in electrostatics.

ChloeFoulkes
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Homework Statement



The electric field on the x-axis due to a point charge fixed at the origin is given by E=(a/x2)i, where a = 6.00 kVm and x is not equal to zero.
a) Find the magnitude and sign of the point charge
b) Find the potential difference between the points on the x-axis at x=1 m and x=2 m.
c) What is the potential energy of a proton at both positions?


Homework Equations



E=kq/^2
Vb-Va=-∫Edl

The Attempt at a Solution



a) I've got the magnitude but I am unsure how to find the charge?
b) using Vb-Va=-∫Edl, but if I am honest, I am not 100% sure how to use the equation
c) haven't attempted yet
 
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ChloeFoulkes said:

Homework Statement



The electric field on the x-axis due to a point charge fixed at the origin is given by E=(a/x2)i, where a = 6.00 kVm and x is not equal to zero.
a) Find the magnitude and sign of the point charge
b) Find the potential difference between the points on the x-axis at x=1 m and x=2 m.
c) What is the potential energy of a proton at both positions?


Homework Equations



E=kq/^2
Vb-Va=-∫Edl

The Attempt at a Solution



a) I've got the magnitude but I am unsure how to find the charge?
b) using Vb-Va=-∫Edl, but if I am honest, I am not 100% sure how to use the equation
c) haven't attempted yet

What is the magnitude of charge you have calculated ?

For finding the sign of charge ,does the Electric field points towards or away from the point charge placed at the origin ?
 
Last edited:
for a) i equalled a/x^2 and kq/x^2 cancelling to give q=a/k. subbing in values i got 6.67x10^-7 C. How would i know which direction the field is pointing?
 

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