# Final tomorrow loop/mesh analysis using supermeshes

• frixis
In summary, the conversation discussed applying loop analysis to find the current through a 2 ohm resistor and the voltage across a 10 ohm resistor. The equations used were v=ir and KVL, and the attempt at a solution involved using current and loop labels, as well as supermesh. The solution for the first problem involved finding b=1/3, while the second problem involved using equations (1), (2), and (3) to solve for the unknowns.
frixis

## Homework Statement

1 for picture38... apply loop analysis to find the current through the 2 ohm resistor
2 for picture39... apply loop analysis to find the voltage across the 10 ohm resistor

v=ir
kvl

## The Attempt at a Solution

i'm using a, b, c etc as current labels as well as loop names
1)loop a
4a+4(a-b)+4(a-c)=0
condenses to 3a-2b=0

supermesh c&b
-10+8(c-a)+4(b-a)+2b=0

using 2=c-b

condenses to 7b-6a=-3

i get b=1/3... which is so not right...

so wat am i doing wrong??

2)
loop a
4a+75+a+10(a-b)=0

2=c-b

supermesh c&b

-25+2c+10(b-a)+3c=0

wat am i doing wrong again?

i guess supermesh is my problem... or maybe the algebra... but i don't get it... at all.. got an exam tomorrow... so please help quick
thankyou

#### Attachments

• DSC00038.jpg
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• DSC00039.jpg
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Solution to first problem..

Hi mate, I've drawn up a dodgy solution in paint for you, it should help you :)

#### Attachments

• frixishelpwithmesheqs.JPG
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Number 2)

I got for loop a:
4a + a + 10a - 10b +75 = 0
15a - 10b = -75 -----(1)

then for supermesh:
-25 + 2c + 10b - 10a + 3c = 0
-10a + 10b + 5c = 25 ----(2)

then at node N (the node to which the 2A source arrow points)

2 + b - c = 0 therefore c = b+2 ----(3)

sub (3) into (2) then you have two easy eqs to solve

Using KVL at the node is basically your control eq.. it let's you reduce the ueqs down so you can solve them.

Last edited:
thankyou andrew... that rhymes :P
i'm going to save this for future reference.. the solutions that is..

## 1. What is final tomorrow loop/mesh analysis using supermeshes?

Final tomorrow loop/mesh analysis using supermeshes is a method used in circuit analysis to determine the currents and voltages within a circuit. It combines the techniques of loop analysis and mesh analysis to simplify the process and make it more efficient.

## 2. When is final tomorrow loop/mesh analysis using supermeshes used?

This method is typically used when dealing with complex circuits that contain multiple loops and meshes. It can also be used when the circuit contains current sources and voltage sources.

## 3. How does final tomorrow loop/mesh analysis using supermeshes work?

The process involves identifying the supermesh, which is a combination of two or more meshes that share a current source. The supermesh is then treated as a single entity in the analysis, simplifying the calculations and reducing the number of equations needed.

## 4. What are the advantages of using final tomorrow loop/mesh analysis using supermeshes?

One of the main advantages is that it can save time and effort in solving complex circuits, as it combines two methods into one. It also reduces the number of equations needed, making it more efficient and less prone to errors.

## 5. Are there any limitations to using final tomorrow loop/mesh analysis using supermeshes?

While this method can be useful in many cases, it may not be suitable for circuits with multiple current sources that are not connected in a supermesh. In these cases, other methods such as nodal analysis may be more effective.

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