If a ball is dropped down a ramp of any shape, will the acceleration always be 9.8 assuming there is no friction.
I know you can use mgh = 1/2mv^2 to solve for velocity, but can you use vf^2 = vi^2 + 2(a)(d)
The Attempt at a Solution
If you use both equations you get the same answer for final velocity at the bottom of the ramp. However is the acceleration always 9.8 no matter what the shape of the ramp is?