Find a function from a given derivative

notweNcaasI
Messages
1
Reaction score
0

Homework Statement


Find a function F such that F(2) = 0 and F'(x) = sin(e^x)

I think that this a reverse to Part 2 of the Fundamental Theorem of Calc but not really sure.

Homework Equations


From the Theorem:
A(x) = \int f(t) dt

A'(x) = f(x)

f(t) = sin(e^x) ??


The Attempt at a Solution


I attempt to integrate sin(e^x) but that seems like a lost cause.

According to FTC II, the area function with lower limit a=2 is an antiderivative satisfying
F(2) = 0

F(x) = \int^{x}_{2} sin(e^t)dt

Is this the correct function
 
Physics news on Phys.org
That works fine.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top