Find a particular solution for a non-homogeneous differential equation

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SUMMARY

The discussion focuses on finding a particular solution for the non-homogeneous differential equation y'' + 2y' + y = 12.5e-t. The user initially attempts to apply the method of undetermined coefficients but struggles with the choice of the particular solution, yp = e-t, which is incorrect as it is a solution to the associated homogeneous equation. The correct approach involves modifying the particular solution to account for the repeated root of the characteristic equation, r = -1, which necessitates using a modified form such as yp = t*e-t.

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blouqu6
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Find a particular solution for the following equation:

y"+2y'+y=12.5e-t

I'm not sure on which method to use. Here's my attempt using the undetermined coefficients method:

→y"+2y'+y=12.5e-t
r2+2r+1=0
r=-1 *not even sure if this part is useful

→yp=e-t
yp'=-e-t
yp"=e-t

→y"+2y'+y=12.5e-t
(e-t)+2(-e-t)+(e-t)=12.5e-t

e-t(1-2+1)=e-t(12.5)

This is where I get stuck; I don't believe I'm taking the right approach from the get-go. Any help would be greatly appreciated.
 
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blouqu6 said:
Find a particular solution for the following equation:

y"+2y'+y=12.5e-t

I'm not sure on which method to use. Here's my attempt using the undetermined coefficients method:

→y"+2y'+y=12.5e-t
r2+2r+1=0
r=-1 *not even sure if this part is useful
It's very useful, as it gives you the complementary solution, the solution to the homogeneous problem. Note that r = -1 is a repeated solution of the characteristic equation.
blouqu6 said:
→yp=e-t
Not a good choice for a particular solution. e-t is a solution of the homogeneous problem, so can't possibly be a solution of the nonhomogeneous problem.
blouqu6 said:
yp'=-e-t
yp"=e-t

→y"+2y'+y=12.5e-t
(e-t)+2(-e-t)+(e-t)=12.5e-t

e-t(1-2+1)=e-t(12.5)

This is where I get stuck; I don't believe I'm taking the right approach from the get-go. Any help would be greatly appreciated.
 

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