- #1
blouqu6
- 3
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Find a particular solution for the following equation:
y"+2y'+y=12.5e-t
I'm not sure on which method to use. Here's my attempt using the undetermined coefficients method:
→y"+2y'+y=12.5e-t
r2+2r+1=0
r=-1 *not even sure if this part is useful
→yp=e-t
yp'=-e-t
yp"=e-t
→y"+2y'+y=12.5e-t
(e-t)+2(-e-t)+(e-t)=12.5e-t
e-t(1-2+1)=e-t(12.5)
This is where I get stuck; I don't believe I'm taking the right approach from the get-go. Any help would be greatly appreciated.
y"+2y'+y=12.5e-t
I'm not sure on which method to use. Here's my attempt using the undetermined coefficients method:
→y"+2y'+y=12.5e-t
r2+2r+1=0
r=-1 *not even sure if this part is useful
→yp=e-t
yp'=-e-t
yp"=e-t
→y"+2y'+y=12.5e-t
(e-t)+2(-e-t)+(e-t)=12.5e-t
e-t(1-2+1)=e-t(12.5)
This is where I get stuck; I don't believe I'm taking the right approach from the get-go. Any help would be greatly appreciated.