Find Amplitude and Equilibrium in Simple Harmonic Motion

AI Thread Summary
To find the amplitude and equilibrium position of a particle in simple harmonic motion, the equilibrium position (xeq) can be calculated using the midpoint formula: (x1 + x2)/2, which results in xeq = 0.035 m. The amplitude (A) is determined by the distance from the equilibrium position to either extreme, calculated as |x2 - xeq| or |x1 - xeq|, yielding A = 0.384 m. The frequency (f) can be found using the period (T) with the formula f = 1/T, resulting in f = 1.96 Hz. Understanding these relationships is essential for solving problems related to simple harmonic motion. The discussion emphasizes the importance of visualizing the system to clarify these concepts.
jcd2012
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Homework Statement



A 0.241-kg particle undergoes simple harmonic motion along the horizontal x-axis between the points x1 = -0.349 m and x2 = 0.419 m. The period of oscillation is 0.511 s. Find the frequency, f, the equilibrium position, xeq, the amplitude, A.

Homework Equations



The hint system suggests:

Midpoint Formula: (X_1 + X_2)/2
Distance Between Two Points: |X_1 - X_2|

The Attempt at a Solution



I am just not sure how I get amplitude and equilibrium from this information. The hint system suggests that I draw the setup to determine these however I am lost from there.
 
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I would suggest you consider the definitions and equations of frequency, equilibrium and amplitude. After drawing the system, consider how these quantities are represented in the system.
 

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