Find an ellipse centered through the origin that runs through 3 points

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SUMMARY

The discussion focuses on finding the equation of an ellipse centered at the origin that passes through the points (1,2), (2,2), and (3,1). The equation is expressed in the general form $$ ax^2 + bxy + cy^2 = 1 $$, which allows for ellipses that may not have axes parallel to the coordinate axes. Participants clarify that while $$ (x/a)^2 + (y/b)^2 = 1 $$ describes a standard ellipse, the general form incorporates the term $$ bxy $$ to account for rotation. To derive the specific coefficients a, b, and c, users are advised to substitute the given points into the equation to create a system of equations.

PREREQUISITES
  • Understanding of conic sections and their equations
  • Familiarity with the general form of an ellipse equation
  • Basic algebra for solving systems of equations
  • Knowledge of coordinate geometry
NEXT STEPS
  • Study the derivation of the general form of conic sections
  • Learn how to solve systems of equations with three variables
  • Explore the properties of ellipses and their transformations
  • Investigate the implications of the term $$ bxy $$ in conic equations
USEFUL FOR

Mathematicians, students studying conic sections, and anyone interested in geometric transformations and their applications in algebra.

mahrap
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Find the ellipse centered at the origin that runs through
the points (1,2), (2,2), and (3, I). Write your equation
in the form $$ ax^2 + bxy + cy^2 = 1 $$

I understand the $$ ax^2 $$ and $$ cy^2 $$ in the equation because the equation of an ellipse centered at origin is $$ (x/a)^2 + (y/b)^2 = 1 $$ so we let $$ a = (1/a)^2 $$ and $$ b = (1/b)^2 $$. but where did the $$ bxy $$ come from?
 
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mahrap said:
Find the ellipse centered at the origin that runs through
the points (1,2), (2,2), and (3, I). Write your equation
in the form $$ ax^2 + bxy + cy^2 = 1 $$

I understand the $$ ax^2 $$ and $$ cy^2 $$ in the equation because the equation of an ellipse centered at origin is $$ (x/a)^2 + (y/b)^2 = 1 $$ so we let $$ a = (1/a)^2 $$ and $$ b = (1/b)^2 $$. but where did the $$ bxy $$ come from?

##(x/a)^2 + (y/b)^2 = 1## is only the equation of an ellipse centered at the origin whose axes are parallel to x and y axes. ##ax^2 + bxy + cy^2 = 1## is more general. It may be at an angle. Just put the given values for x and y in and get three equations to solve for the three unknowns a, b and c.
 

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