# Find angular acceleration of a yoyo

1. Sep 23, 2010

### Raziel2701

1. The problem statement, all variables and given/known data
A Yo-Yo is made up of twp solid disks each with radius R and mass M. The axle has radius r and is essentially massless. The Yo Yo is released to unwind.
Find the angular acceleration of the YoYO as it falls in terms of r, R and g.

2. Relevant equations
$$\Sigma\tau=I\alpha$$

I = 1/2MR^2

I set up the sum of torques to be the tension from the string times r, plus 2MgR, though I don't see what difference there would be if it were 2Mgr:

$$\Sigma\tau=Tr +2MgR=I\alpha$$

I setup the following too:

$$\Sigma\F_y = T -2Mg = 2Ma$$ To solve for T and substitute into my equation for the sum of torques.

Then solving for $$\alpha$$ I finally get:

$$\frac{g(r+R) + ar}{R^2}$$ I don't think my answer should have a term for linear acceleration, unless it's gravity too?

I feel like I'm doing things blindly. I know that the sum of torques should equal the moment of inertia times the angular acceleration, but this business with the different radii is confusing me and I am uncertain as to whether or not what I'm doing makes sense.

UNRELATED: I tried previewing the post after doing some modifications and it shows all out of formatting. Please excuse any oddities.

2. Sep 23, 2010

### Raziel2701

I think I read too much into the problem. If the yo yo is falling, given the context of the problem there is no mention or too much emphasis on the string being unwounded, so I know that it's rotating but there's nothing to lead me to believe that there's a tension.

So setting up the sum of torques I get:

$$\Sigma\tau=2Mgr=I\alpha$$

Solving for alpha I get

4gr/R^2

Still, does this result make sense? I don't really have a way of checking my answer since this homework is just something we turn in. So, I was wondering, if r, the axle was very small, say even zero, then there would be no angular acceleration for the yoyo wouldn't rotate right?

So at least the equation makes sense that way I suppose?

3. Sep 24, 2010

### kjohnson

If there was no tension there would be no torque and no angular acceleration...you had the right idea above, you just need the relationship between linear acceleration and angular acceleration.