Find Change in Charge of Identical Capacitors w/ Dielectric Insertion

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The discussion focuses on calculating the change in charge for two identical capacitors with a capacitance of 1.20 F connected in series across a fixed potential of 650 V when a dielectric slab with a dielectric constant of 3.70 is inserted. The relevant equation for capacitance with a dielectric is C = C₀K. Participants are uncertain about which capacitor the dielectric is inserted into, but it is suggested that it is the first one. The equivalent capacitance of the series configuration needs to be determined, and the charge can be calculated using the relationship Q = CV. The charge on each capacitor remains the same as the charge calculated for the equivalent capacitor.
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Homework Statement


Two identical capacitors and of capacitance 1.20 F are connected in series across a FIXED total potential of 650 V. A dielectric slab of dielectric constant 3.70 can fill and is slowly inserted into that capacitor.
1. What is the change in charge, , on when the dielectric is added to ?
2. What is the change in charge, , on when the dielectric is added to ?

Homework Equations


C=C_{o}K

The Attempt at a Solution


Not quite sure.
 
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Use Q = CV. which capacitor is the dielectric inserted into?
 
the first one
 
Winzer said:
the first one

What is the equivalent capacitance of the two series capacitors? Use the Q=CV relationship to get the charge on the equivalent capacitor...

The charge on each capacitor is the same as the charge you get above...
 
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