Find Delta r for Particle Displacement of 65m in 41° Direction

AI Thread Summary
To find the particle's displacement in terms of unit vectors, the x-component is calculated as cos(41°) * 65, resulting in approximately 48 m. The y-component requires using sin(41°) * 65, but since the displacement is below the x-axis, the y value should be negative. Thus, the correct expression for Delta r is approximately 48i - 42.5j, where 42.5 is the result of sin(41°) * 65. Properly accounting for the direction of the displacement is crucial for accurate calculations.
IUBritt09
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Hey! I have been trying this problem forever and can't seem to figure out the answer for y. I thought that I was supposed to take sin(41)*65?? But that answer keeps coming up as wrong?? Any help would be amazing!

A particle undergoes a displacement of magnitude 65 m in a direction 41° below the x axis. Express in terms of the unit vectors y and x.

find: Delta r= _____X + ______y

I am unsure how to fingue out how to get my y value. For x I took cos(41)*65=48, but I am unable to figure out how to find y?
 
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Have you taken into account the fact that the particle was displaced below the x-axis and thus y is negative?
 
That problem would not occur if you took 41 degrees below the x axis, as 319 degrees absolute.
 

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