Find Distance Compressed by Spring w/ Kinetic Friction

AI Thread Summary
To find the distance a spring is compressed by an object under kinetic friction, the equation x = (W - μkN) / k is used, where W is the object's weight, μk is the coefficient of kinetic friction, N is the normal force, and k is the spring constant. The normal force can be calculated as N = mg, with m being the object's mass and g the acceleration due to gravity. The weight is determined by multiplying the mass by gravity. This equation applies only when the object is in motion; if at rest, static friction must be considered instead. Ultimately, understanding these dynamics allows for accurate calculations of spring compression in the presence of friction.
senseandsanity
Messages
10
Reaction score
0
How do you find the distance a spring is compressed by an object when kinetic friction is involved?
 
Physics news on Phys.org
senseandsanity said:
How do you find the distance a spring is compressed by an object when kinetic friction is involved?

Write Newton's second principle of dynamics in mathematical form including all the forces (they are only 2:the friction and the elastic force).To integrate the resulting ODE equation,your friction force must depend linearly on the speed (the example of viscous Stokes forces in fluids).From there,u'll find how the spring will oscilate.

The spring's compression understood as the amplitude of oscillation will decrease exponentially with time,so,eventually (for asymptotic times:t->+infinity),due to friction,the oscillations will stop and the body will stop as well.Where??That's impossible to tell,if u're in the "sin/cos" regime of oscillation.
 

To find the distance a spring is compressed by an object when kinetic friction is involved, we can use the following equation:

x = (W - μkN) / k

where x is the distance the spring is compressed, W is the weight of the object, μk is the coefficient of kinetic friction, N is the normal force, and k is the spring constant.

First, we need to determine the normal force acting on the object. This can be done by using the equation N = mg, where m is the mass of the object and g is the acceleration due to gravity.

Next, we need to determine the weight of the object, which is simply the mass of the object multiplied by the acceleration due to gravity.

Once we have these values, we can plug them into the equation to find the distance the spring is compressed. The coefficient of kinetic friction, μk, can be found by conducting experiments or by looking it up in a table.

It is important to note that this equation only applies when the object is in motion and experiencing kinetic friction. If the object is at rest, then we need to use the equation for static friction to calculate the distance the spring is compressed.

In summary, to find the distance a spring is compressed by an object when kinetic friction is involved, we need to use the equation x = (W - μkN) / k, where W is the weight of the object, μk is the coefficient of kinetic friction, N is the normal force, and k is the spring constant.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Building a Marble Catapult
Replies
3
Views
871
Distribution of Energy when work is done on a system of 2 masses connected by a spring
Replies
17
Views
1K
Find elastic energy in the compressed spring.
Replies
12
Views
3K
Problem with when to use Force and Energy. What compresses spring/
Replies
3
Views
1K
Conservation: Mass Dropped onto a Spring, Find the Compression
Replies
9
Views
2K
Calculating the spring force constant K
Replies
14
Views
2K
A block dropping onto a spring system
2
Replies
58
Views
2K
Question about springs and rotational/translational energy
Replies
4
Views
1K
Why is my method for finding the spring constant incorrect?
Replies
17
Views
3K
A rocket on a spring, related to potential/kinetic energy
Replies
3
Views
2K

Hot Threads

Recent Insights

Back
Top