Find electric and magnetic field amplitudes in an electromagnetic wave

AI Thread Summary
To find the electric and magnetic field amplitudes in an electromagnetic wave with an average energy density of 1 J/m^3, the relevant equations include u = (1/2)(ε0)(E^2) and u = (B^2)/μ0. The initial calculations for E yielded 336146 V/m and for B, 0.001121 T, but these were incorrect as they represented RMS values rather than peak values. The correct approach involves multiplying the RMS values by √2 to obtain the peak amplitudes. After applying this adjustment, the values for E and B can be accurately determined.
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[Solved] Find electric and magnetic field amplitudes in an electromagnetic wave

Homework Statement



Find the electric and magnetic field amplitudes in an electromagnetic wave that has an average energy density of 1 J/m^3

Homework Equations



u = Energy density
u = (1/2)(e0)(E^2) + (1/2)(B^2/u0)
or u = (e0)(E^2)
or u = (B^2)/u0

E = cB, c = speed of light

The Attempt at a Solution



Let's find E first:
u = e0*E^2
E = sqrt(u/e0) = sqrt(1/(8.85*10^-12)) = 336146 V/m
336146 V/m is apparently wrong for E. Let's try B instead

u = (B^2)/u0
B = sqrt(u*u0) = 0.001121 T
Now let's try E = cB to find E
E = (3*10^8)(0.001121) = 336300 V/m

But both E and B are wrong. What am I missing? Percent error tolerance for a correct answer is 10%.
 
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I think your answers are for the RMS values of the fields, rather than for the peak values. The peak values are generally used for the amplitude of a wave.

Try multiplying your answers by √(2) .
 
Edit: This is the equation I used, I have Uav = 1 J/m^3

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Edit: Oh, I see. Thanks. :)
 
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