Electric Field from 2.5uC Point Charge at 0.75m

AI Thread Summary
To find the electric field produced by a 2.5 µC point charge at a distance of 0.75 m, the formula E = kq/r^2 is used, resulting in E = 400 x 10^9 V/m. There is no need to convert units since N/C is equivalent to V/m, and the units from the equation naturally cancel out. The calculations appear correct based on the provided values. The user seeks confirmation of their answer and the correctness of their approach. Overall, the discussion emphasizes the accuracy of the electric field calculation and unit consistency.
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Homework Statement



Find the electric field produced by a 2.5uC point charge at distance of 0.75m.

E = ___ V/m

Homework Equations



E = kq/r^2

The Attempt at a Solution



E = (9x10^9 Nm^2/C^2)(25)/(0.75)^2 = 400 x 10^9

My concern is about the units I am being asked. Since K is using Nm^2/C^2, how do I convert it to V/m IF IT´S CORRECT, of course.

Thanks in advance!
 
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N/C is equivalent to V/m. There is no need to worry about conversions. The units of K cancel with the ones for q and r^2 to give you N/C
 
Hi, thanks for the reply. Does my answer seem correct to you? Am I on the right track?
 
Anyone? Please, time is really short for me and I really need quick help here. Please.
 
I just need a confirmation. I posted the calculus and values. Are they correct?
 
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