Find equation for thermodynamic process

AI Thread Summary
The discussion centers on finding the equation for a thermodynamic process where the specific heat is defined as C = R/(\gamma - 1) + αP. Participants clarify that C represents the specific heat capacity of the process, distinct from constant pressure or volume values. The first law of thermodynamics is suggested as a method to proceed with the calculations. There is a debate about the validity of using ΔQ = nCΔT across different processes, with consensus that it applies universally. Ultimately, the original poster successfully arrives at the correct answer.
utkarshakash
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Homework Statement


Find the equation of the thermodynamic process in which specific heat of the gas is given by

C=\dfrac{R}{\gamma -1} + \alpha P

The Attempt at a Solution



I can write

C=C_v + \alpha P

But I don't know how to proceed ahead. What does C mean here? Is it specific heat capacity at constant pressure or volume? Any help is appreciated.
 
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utkarshakash said:

Homework Statement


Find the equation of the thermodynamic process in which specific heat of the gas is given by

C=\dfrac{R}{\gamma -1} + \alpha P


The Attempt at a Solution



I can write

C=C_v + \alpha P

But I don't know how to proceed ahead. What does C mean here? Is it specific heat capacity at constant pressure or volume? Any help is appreciated.
Is α supposed to be the coefficient of volumetric thermal expansion? Because, if it is, it's units are wrong.

Chet
 
Chestermiller said:
Is α supposed to be the coefficient of volumetric thermal expansion? Because, if it is, it's units are wrong.

Chet

No. It's a positive constant.
 
Hi utkarshakash

utkarshakash said:
I can write

C=C_v + \alpha P

Correct...

utkarshakash said:
But I don't know how to proceed ahead. What does C mean here? Is it specific heat capacity at constant pressure or volume? Any help is appreciated.

C is the specific heat capacity of the process .It is neither of the two (i.e at constant pressure or volume ) .It is not that the heat capacity has to be either CP or CV .

Apply the first law of thermodynamics .
 
Tanya Sharma said:
Hi utkarshakash



Correct...



C is the specific heat capacity of the process .It is neither of the two (i.e at constant pressure or volume ) .It is not that the heat capacity has to be either CP or CV .

Apply the first law of thermodynamics .

I get
m(C_v + \alpha P) dT = nC_vdT + \int P dV

where m=mass of gas
How do I calculate the work done in the process?
 
utkarshakash said:
m(C_v + \alpha P) dT = nC_vdT + \int P dV

where m=mass of gas

I think it should be

nCdT = nCVdT + pdV

Write Cv in terms of C and take n =1 for sake of simplicity.
 
Tanya Sharma said:
I think it should be

nCdT = nCVdT + pdV

Write Cv in terms of C and take n =1 for sake of simplicity.

But ΔQ=nCΔT is valid only when C=Cp. In general ΔQ=mCΔT
 
utkarshakash said:
But ΔQ=nCΔT is valid only when C=Cp. In general ΔQ=mCΔT

:rolleyes:

ΔQ=nCΔT is applicable in every process.
 
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Tanya Sharma said:
:rolleyes:

ΔQ=nCΔT is applicable in every process.

Thanks. I got the correct answer.
 
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