Find Equation of Elipse with b=3, M(-2SQRT(5),2)

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To find the equation of the ellipse with b=3 and the point M(-2SQRT(5), 2) on it, the standard form x^2/a^2 + y^2/b^2 = 1 is used. The calculations initially led to the equation x^2/4 + y^2/9 = 1, suggesting a=2. However, a mistake was identified in the manipulation of the equation, specifically in the step involving 20 + 4a^2/9 = a^2. Correcting this gives 180 + 4a^2 = 9a^2, leading to the correct solution. The final verified equation of the ellipse is 9x^2 + 36y^2 = 324.
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Homework Statement


Find equation of elips if b=3 and point M(-2SQRT(5), 2) is on elipse.

Homework Equations



x^2/a^2 + y^2/b^2 = 1

The Attempt at a Solution


x^2/a^2 + y^2/b^2 = 1

20/a^2 + 4/9 = 1

20/a^2 + 4/9 = 1 / * a^2

20 + 4a^2/9 = a^2

20 + 4^2 = 9a^2

20= 5a^2

a = 2

so equation of elipse is x^2/4 + y^2/9 = 1

But answer at the end of a book is 9x^2 + 36y^2 = 324

Which one is correct?
 
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This bit:

20 + 4a^2/9 = a^2

20 + 4a^2 = 9a^2

is wrong, because you should multiply the 20 by 9 too. Equation should become

180 + 4a^2 = 9a^2, which would give you the right solution.
 
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