Find equations of the tangent lines to the curve

[balla123]

Find equations of the tangent lines to the curve y=(lnx)/x
at the points (1,0) and (e,1/e) . Illustrate by graphing the
curve and its tangent lines.


i found that the derivative is 1-lnx/x^2

what do i do next? thanks

 

[rock.freak667]

I did not check your derivative, but you have dy/dx = (1-lnx)/x²

to get the gradient at any point 'x'. Just put that value of 'x' in the expression for 'dy/dx' and you will get the gradient of the tangent at that point.