Find f(x) given properties of the derivatives.

Skizye
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Homework Statement


Let f be a differentiable function, defined for all real numbers x, with the following properties:

1. f'(x) = ax^2 + bx

2. f'(1) = 6 and f"(1) = 18

3. \int_{1}^{2} f(x)dx = 18

Find f(x).

Homework Equations


The Attempt at a Solution


Using the first two properties, I did some algebra (solve the second derivative equation for b and write the first derivative equation in terms of a and solve), and found that a = 12 and b = -6. Using this I took the intergral of the first derivative and got this:

f(x) = 4x^3 - 3x^2 + c

The problem is that this equation doesn't satisfy the 3rd property. Is what I have so far correct? If not, how can I account for that 3rd property when I'm solving for a/b and finding f(x)? Thanks!
 
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If you integrate f(x) = 4x^3 -3x^2 +c you get x^4 - x^3 + cx +d .

Evaluating the integral at the limits, you will arrive at a value for c that satifies all properties.
 
Skizye said:

Homework Statement


Let f be a differentiable function, defined for all real numbers x, with the following properties:

1. f'(x) = ax^2 + bx

2. f'(1) = 6 and f"(1) = 18

3. \int_{1}^{2} f(x)dx = 18

Find f(x).

Homework Equations





The Attempt at a Solution


Using the first two properties, I did some algebra (solve the second derivative equation for b and write the first derivative equation in terms of a and solve), and found that a = 12 and b = -6. Using this I took the intergral of the first derivative and got this:

f(x) = 4x^3 - 3x^2 + c

The problem is that this equation doesn't satisfy the 3rd property.
It will if you find the correct value for c.

Your values for a and b are correct. Now, since you know the value of the integral of f, you can solve for c.
Skizye said:
Is what I have so far correct? If not, how can I account for that 3rd property when I'm solving for a/b and finding f(x)? Thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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